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0.7x^2-1.3x-2=0
a = 0.7; b = -1.3; c = -2;
Δ = b2-4ac
Δ = -1.32-4·0.7·(-2)
Δ = 7.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.3)-\sqrt{7.29}}{2*0.7}=\frac{1.3-\sqrt{7.29}}{1.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.3)+\sqrt{7.29}}{2*0.7}=\frac{1.3+\sqrt{7.29}}{1.4} $
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